[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: 256MB of RAM w/Pentium 233
On Wed, 9 Dec 1998, Keyser Soze wrote:
> hw.physmem = 268042240
> hw.usermem = 255320064
> machdep.bios.cnvmem = 639
> machdep.bios.extmem = 261120
> How can I tell that all my memory is being seen/used?
256 megs is seen
> Here is some output from dmesg. What does each line really mean?:
> BIOS mem = 654336 conventional, 267386880 extended
> real mem = 268042240
> avail mem = 194031616
> using 2822 buffers containing 67534848 bytes of memory
You have BUFCACHEPERCENT=.... and that's using sixty some megs of memory
along with some other buffers and space allocated according to your
'maxusers' so you have <200 megs available afterwards
> "top" reports this:
> 233 processes: 1 running, 232 idle
> Memory: Real: 106M/183M act/tot Free: 3052K Swap: 24M/128M used/tot
> what is "act/tot" and why does it start using swap so soon?
It pages out stuff that isn't being used! Chances are that it isn't
actually doing much swapping since you don't have 183M active?
> The server is a heavily used web, ftp, shell server.
> Thank you for any advice.
*--chris at satelnet.org--*