Re: 256MB of RAM w/Pentium 233

[Chris <chris@sefl.satelnet.org>]

On Wed, 9 Dec 1998, Keyser Soze wrote:

> hw.physmem = 268042240
> hw.usermem = 255320064
> machdep.bios.cnvmem = 639
> machdep.bios.extmem = 261120
> 
> How can I tell that all my memory is being seen/used?
> 

256 megs is seen

> Here is some output from dmesg. What does each line really mean?:
> 
> BIOS mem  = 654336 conventional, 267386880 extended
> real mem  = 268042240
> avail mem = 194031616
> using 2822 buffers containing 67534848 bytes of memory
> 

You have BUFCACHEPERCENT=.... and that's using sixty some megs of memory
along with some other buffers and space allocated according to your
'maxusers' so you have <200 megs available afterwards

> "top" reports this:
> 233 processes: 1 running, 232 idle
> Memory: Real: 106M/183M act/tot  Free: 3052K  Swap: 24M/128M used/tot
> 
> what is "act/tot" and why does it start using swap so soon?
> 

active/total

It pages out stuff that isn't being used! Chances are that it isn't
actually doing much swapping since you don't have 183M active?

> The server is a heavily used web, ftp, shell server.
> 
> Thank you for any advice.
> 
> 
> 
> 

*--chris at satelnet.org--*